【Vijos1308】埃及分数 – 徐亦轲的博客

刷水题ing

做的第一道迭代加深题（也是最经典的一道）

（这么水应该就不要讲了吧

// <1308.cpp> - 03/11/16 00:02:32
// This file is created by XuYike's black technology automatically.
// Copyright (C) 2015 ChangJun High School, Inc.
// I don't know what this program is.

#include <iostream>
#include <vector>
#include <algorithm>
#include <cstring>
#include <cstdio>
#include <cmath>
using namespace std;
typedef long long lol;
int getint(){
	int res=0,fh=1;char ch=getchar();
	while((ch>'9'||ch<'0')&&ch!='-')ch=getchar();
	if(ch=='-')fh=-1,ch=getchar();
	while(ch>='0'&&ch<='9')res=res*10+ch-'0',ch=getchar();
	return fh*res;
}
int D;
lol ans[100],ANS[100];
void tf(lol &a,lol &b){
	lol k=__gcd(a,b);
	a/=k;b/=k;
}
bool src(lol a,lol b,int d){
	if(d++==D){
		if(a)return 0;
		if(!ANS[D]||ans[D]<ANS[D])for(int i=1;i<=D;i++)ANS[i]=ans[i];
		return 1;
	}
	bool r=0;
	ans[d]=max(ans[d-1]+1,(b-1)/a+1);
	for(;;ans[d]++){
		if((D-d+1)*b<a*ans[d])break;
		lol na=a*ans[d]-b,nb=b*ans[d];
		tf(na,nb);
		r|=src(na,nb,d);
	}
	return r;
}
int main(){
	lol a=getint(),b=getint();
	tf(a,b);
	for(ans[0]=0;b>a*ans[0]+a;ans[0]++);
	for(D=1;;D++)
		if(src(a,b,0)){
			for(int i=1;i<=D;i++)printf("%lld ",ANS[i]);
			return 0;
		}
}

// <1308.cpp> - 03/11/16 00:02:32

// This file is created by XuYike's black technology automatically.

// I don't know what this program is.

#include <iostream>

#include <vector>

#include <algorithm>

#include <cstring>

#include <cstdio>

#include <cmath>

using namespace std;

typedef long long lol;

int getint(){

int res=0,fh=1;char ch=getchar();

while((ch>'9'||ch<'0')&&ch!='-')ch=getchar();

if(ch=='-')fh=-1,ch=getchar();

while(ch>='0'&&ch<='9')res=res*10+ch-'0',ch=getchar();

return fh*res;

}

int D;

lol ans[100],ANS[100];

void tf(lol &a,lol &b){

lol k=__gcd(a,b);

a/=k;b/=k;

}

bool src(lol a,lol b,int d){

if(d++==D){

if(a)return 0;

if(!ANS[D]||ans[D]<ANS[D])for(int i=1;i<=D;i++)ANS[i]=ans[i];

return 1;

}

bool r=0;

ans[d]=max(ans[d-1]+1,(b-1)/a+1);

for(;;ans[d]++){

if((D-d+1)*b<a*ans[d])break;

lol na=a*ans[d]-b,nb=b*ans[d];

tf(na,nb);

r|=src(na,nb,d);

}

return r;

}

int main(){

lol a=getint(),b=getint();

tf(a,b);

for(ans[0]=0;b>a*ans[0]+a;ans[0]++);

for(D=1;;D++)

if(src(a,b,0)){

for(int i=1;i<=D;i++)printf("%lld ",ANS[i]);

return 0;

}

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